Access this content offline
Omniguides
Skip to the reading

The Chain Rule

Identify composition layers, evaluate each rate at the correct input, and include every inside factor.

This is shared AB/BC instruction. Open the AB edition of Topic 3.1. Your BC practice and progress stay in this book.

College Board Topic 3.1 · CED p. 70 (PDF p. 75) · CED effective Fall 2020; project course outline 2026–27.

A composition changes in layers. If y=f(u) and u=g(x), then dy/dx=(dy/du)(du/dx), provided the component derivatives exist at the relevant inputs. In function notation, (f∘g)′(x)=f′(g(x))g′(x). Differentiate the outside while leaving the inside in place, then multiply by the inside rate.

For y=(3x²+1)⁴, the outside rule gives 4(3x²+1)³ and the inside rate is 6x, so y′=24x(3x²+1)³. For y=sin(x²), y′=cos(x²)·2x. For y=e^(−x), y′=−e^(−x). Missing the inside factor is the most common error.

More layers mean more factors. For y=ln(1+e^(2x)), the layers are log, addition, exponential and 2x. The derivative is [1/(1+e^(2x))]·e^(2x)·2. With table data, evaluate the outside derivative at the inside output: if g(2)=5, the outside derivative needed is f′(5), not f′(2). Units can reveal the structure: meters per liter times liters per minute gives meters per minute.

Let's work through it

  1. For y=sin(3x²), identify outside sin u and inside u=3x². Reason: the expression is a composition.
  2. The outside derivative is cos(3x²); the inside derivative is 6x. Reason: differentiate each layer at its own input.
  3. Multiply to get y′=6x cos(3x²). Reason: the chain rule combines the rates through the layers.

Try it from memory

Pause & retrieve

Try it before you peek.

Write your answer and the reason from memory. Then compare with the worked answer. Your self-assessment is a study decision, not an automatically graded score.

Question 1 of 20 self-assessed

Question 1

Differentiate (2x+1)⁵.

See every recall question with its answer

These references preserve each prompt and its answer for direct evidence links. Try the interactive questions above before opening the worked reasoning.

Retrieval 1

Differentiate (2x+1)⁵.

Worked answer and reason

10(2x+1)⁴.

The outside factor is 5(2x+1)⁴ and the inside rate is 2.

Retrieval 2

If g(1)=4, g′(1)=−2 and f′(4)=3, find (f∘g)′(1).

Worked answer and reason

−6.

Evaluate the outside derivative at g(1)=4, then multiply by g′(1).

Catch the tempting mistake

Differentiate the outside and ignore the inside because it is unchanged.
The inside remains in the outside formula, but its rate still multiplies the result.

Make the picture move

Explore → predict → explain

A derivative is a limit of slopes.

Try first. At the selected a, predict the tangent slope. Which side’s secant lies above it, and which lies below?

f(x)=x2f′(a)=limh→0f(a+h)−f(a)h
A derivative is a limit of slopes.A solid function graph, a dashed secant through the two labeled points, and a dotted exact tangent. Right secant slope 2.5 at a = 1. The derivative is 2. The numerical table and explanation follow the graph.-2.6-1.301.32.6-11.053.15.157.2aa+hxy

Scroll sideways to see the full graph on a small screen. The table below gives the numerical values.

  • Function: x²
  • Selected secant
  • Exact tangent
A solid function graph, a dashed secant through the two labeled points, and a dotted exact tangent. Right secant slope 2.5 at a = 1. The derivative is 2.
Input a1
Selected secant slope2.5
Exact derivative2

Right secant slope 2.5 at a = 1. The derivative is 2.

Compare the numbers
Computed values for this scenario (rounded for display)
Distance |h|Left secant slopeRight secant slope
0.51.52.5
0.251.752.25
0.11.92.1
0.051.952.05

What’s going on? For x², the difference quotient simplifies to 2a + h. As h approaches zero from either side, the secant slope approaches 2a.

Keep in mind. The controls keep h nonzero so that the quotient is defined. A small h is an approximation; the limiting calculation supplies the exact derivative.

Calculator workspace and limits

For calculus, set the angle selector to Radians. This scientific calculator evaluates arithmetic and functions. It does not graph arbitrary functions, find numerical roots, evaluate numerical derivatives, or compute definite integrals. Those tasks need an approved graphing tool; the May 2027 exam permits approved handheld graphing calculators and Bluebook’s built-in Desmos on calculator-required parts. A graph or decimal estimate helps you check a conclusion; your setup, hypotheses, units and justification still do the explaining.

Scientific calculator

This calculator requires JavaScript. Use the physics formula sheets and show your working manually.

Calculation is unavailable without JavaScript.

+ − * / ^ ! · pi · e · sqrt · sin, cos, tan · asin, acos, atan · atan2(y,x) · ln, log · abs · exp · hypot(x,y). Use * between factors. Keep units in your written working.

Put it to work

For the teacher
  • Use a labeled layer diagram before symbolic calculation.
  • Mix analytic formulas with table and unit-based chain reasoning.

Unit planning and formative guidance →

Glossary and deeper reading · 2 refreshers

These editorial refreshers supplement the reading. Definitions and examples are added guidance; original source wording and recorded answers remain in their original context.

  • Derivative

    A derivative gives the instantaneous rate of change of a function with respect to its input. At a point, it is the finite limit of the difference quotient when that limit exists. For example, the derivative of x² is 2x, so the tangent slope at x=3 is 6. A derivative function collects those rates across the inputs where the function is differentiable.

    Read more: 2.2 · Derivative →

  • Function

    A mathematical function assigns exactly one output to each input in its domain. Inputs can share an output, but one input cannot have two different outputs. For example, f(x)=x² assigns the output 9 to both 3 and −3. Function notation names the rule and its input; f(3) means the output when the input is 3.

Search lessons, terms and problems