Access this content offline
Omniguides
Skip to the reading

Using the Second Derivative Test to Determine Extrema

Apply the second derivative test at stationary points and use a different argument when it is inconclusive.

This is shared AB/BC instruction. Open the AB edition of Topic 5.7. Your BC practice and progress stay in this book.

College Board Topic 5.7 · CED p. 100 (PDF p. 105) · CED effective Fall 2020; project course outline 2026–27.

At a stationary critical number c with f′(c) = 0, the second derivative test can classify the turn. Under the usual local differentiability conditions, f″(c) > 0 gives a local minimum and f″(c) < 0 gives a local maximum. The curve bends upward or downward around a horizontal tangent. First verify that the tangent is horizontal; concavity alone does not create an extremum.

If f″(c) = 0 or is unavailable, this test is inconclusive. Go back to derivative sign changes or direct comparison. The functions x⁴, −x⁴, and x³ all have first and second derivative zero at the origin, yet they give a minimum, maximum, and neither. One zero calculation cannot distinguish them.

Local and absolute conclusions still need different evidence. The CED also includes a useful one-critical-point case: when a continuous function on a domain interval has only one critical point, and that point is a local extremum, it is the corresponding absolute extremum on that interval. Continuity and the complete critical-point count matter. Any competing turn inside the interval would require another critical point. An equivalent practical proof is to show the function decreases all the way into a minimum and increases all the way away.

For f(x) = x + 4/x on (0,∞), f′ = 1 − 4/x² has only c = 2, and f″ = 8/x³ > 0. It is a local minimum; the unique-critical-point criterion makes it absolute. Directly, f′ is negative before 2 and positive after 2. On closed intervals with multiple candidates, use a complete candidates comparison instead.

Let's work through it

  1. For f(x) = x³ − 12x, f′ = 3x² − 12 gives critical numbers −2 and 2.

    Why: Solve the stationary-point condition before applying the test.

  2. f″(x) = 6x; f″(−2) = −12 and f″(2) = 12.

    Why: The second derivative supplies local bending at the stationary points.

  3. There is a local maximum at −2 and local minimum at 2.

    Why: Negative/positive second derivative at a stationary point classifies the local extremum.

  4. These are not absolute extrema on all real numbers.

    Why: The cubic tends to opposite infinities, and the one-critical-point condition is not satisfied.

Try it from memory

Pause & retrieve

Try it before you peek.

Write your answer and the reason from memory. Then compare with the worked answer. Your self-assessment is a study decision, not an automatically graded score.

Question 1 of 30 self-assessed

Question 1

What must you check before using f″(c) to classify an extremum?

See every recall question with its answer

These references preserve each prompt and its answer for direct evidence links. Try the interactive questions above before opening the worked reasoning.

Retrieval 1

What must you check before using f″(c) to classify an extremum?

Worked answer and reason

That c is a stationary critical number with f′(c) = 0 and the needed local differentiability conditions hold.

A tilted concave-up curve need not have a minimum at c.

Retrieval 2

What does f″(c) = 0 conclude?

Worked answer and reason

The test is inconclusive.

A first-derivative sign test can distinguish minimum, maximum, and neither.

Retrieval 3

Can one local minimum be absolute on an open interval?

Worked answer and reason

Yes, for a continuous function with exactly one critical point there, as in x + 4/x on (0,∞).

The complete interval behavior prevents another competing turn.

Catch the tempting mistake

The second derivative zero means neither maximum nor minimum.
It means this test cannot decide.
Local minimum automatically means absolute minimum.
You need additional interval evidence, such as a complete candidate comparison or the one-critical-point criterion.
Calculator workspace and limits

For calculus, set the angle selector to Radians. This scientific calculator evaluates arithmetic and functions. It does not graph arbitrary functions, find numerical roots, evaluate numerical derivatives, or compute definite integrals. Those tasks need an approved graphing tool; the May 2027 exam permits approved handheld graphing calculators and Bluebook’s built-in Desmos on calculator-required parts. A graph or decimal estimate helps you check a conclusion; your setup, hypotheses, units and justification still do the explaining.

Scientific calculator

This calculator requires JavaScript. Use the physics formula sheets and show your working manually.

Calculation is unavailable without JavaScript.

+ − * / ^ ! · pi · e · sqrt · sin, cos, tan · asin, acos, atan · atan2(y,x) · ln, log · abs · exp · hypot(x,y). Use * between factors. Keep units in your written working.

Put it to work

For the teacher
  • Make “inconclusive” an acceptable deliberate answer, followed by a different valid test.
  • Ask learners to state the interval and account for all critical points before using the unique-critical-point conclusion.

Unit planning and formative guidance →

Glossary and deeper reading · 8 refreshers

These editorial refreshers supplement the reading. Definitions and examples are added guidance; original source wording and recorded answers remain in their original context.

  • Critical point

    A critical number is an input in the function’s domain where its derivative is zero or does not exist. The corresponding point on the graph is called a critical point. For example, x³ has a critical number at 0, but it has no local maximum or minimum there. Critical numbers are candidates for extrema and need further analysis; inputs outside the domain are excluded.

    Read more: 5.2 · Critical point →

  • Differentiability

    Differentiability means that a function has a finite derivative at the point under discussion. Differentiability at a point implies continuity there, but continuity alone does not imply differentiability. For example, |x| is continuous at 0 but its left and right tangent slopes differ, so it is not differentiable there. Corners, cusps, vertical tangents, and discontinuities can prevent a finite derivative.

    Read more: 2.4 · Differentiability →

  • Derivative

    A derivative gives the instantaneous rate of change of a function with respect to its input. At a point, it is the finite limit of the difference quotient when that limit exists. For example, the derivative of x² is 2x, so the tangent slope at x=3 is 6. A derivative function collects those rates across the inputs where the function is differentiable.

    Read more: 2.2 · Derivative →

  • Function

    A mathematical function assigns exactly one output to each input in its domain. Inputs can share an output, but one input cannot have two different outputs. For example, f(x)=x² assigns the output 9 to both 3 and −3. Function notation names the rule and its input; f(3) means the output when the input is 3.

  • Continuity

    A function is continuous at an input when its value exists, its finite limit exists, and those two values agree. At a domain endpoint, continuity uses the relevant one-sided approach. For example, x² is continuous at 3 because both its value and its nearby limit are 9. Continuity on an interval requires the appropriate condition at every input in that interval.

    Read more: 1.11 · Continuity →

  • Domain

    The domain of a function is the set of inputs for which the function is defined. An expression and its context can both restrict the allowed inputs. For example, the real function f(x)=1/(x−2) has domain all real numbers except 2. For a model of elapsed time, a sensible domain may also require t≥0.

  • Local extremum

    A local extremum is a value at least as large as, or at least as small as, all values at nearby allowed inputs. A local maximum compares nearby heights above, while a local minimum compares them below. For example, x² has a local minimum at 0. A local extremum need not be the greatest or least value over the entire domain.

    Read more: 5.2 · Local extremum →

  • Interval

    An interval is a set of real numbers containing every number between any two of its members. Parentheses exclude an endpoint, while square brackets include it. For example, (1,4] includes 4 and every number between 1 and 4, but excludes 1. An infinite endpoint always uses a parenthesis because infinity is not a real endpoint.

Search lessons, terms and problems