Access this content offline
Omniguides
Skip to the reading

Volumes with Cross Sections: Triangles and Semicircles

Use the specified triangle, semicircle, or circular geometry, distinguishing a supplied radius from a diameter.

This is shared AB/BC instruction. Open the AB edition of Topic 8.8. Your BC practice and progress stay in this book.

College Board Topic 8.8 · CED p. 154 (PDF p. 159) · CED effective Fall 2020; project course outline 2026–27.

A=πs28

Keep V=∫A; change only the geometry of a slice. A triangle has area ½bh, so the problem must tell you the relationship between its base and height. An equilateral triangle with side s has area √3·s²/4. A semicircle with diameter s has radius s/2 and area ½π(s/2)²=πs²/8.

Other specified shapes work the same way: a circle of radius r has A=πr², or the problem may supply A(x) directly. A funnel with circular sections is a cross-section problem even when it is not described as a rotation. Distinguish a base segment described as a diameter from one described as a radius; that factor of 2 changes area by a factor of 4. State the slice direction and keep matching bounds.

Let's work through it

  1. A base segment has length s=2−x on 0≤x≤2, and semicircular slices use it as diameter. Reason: The geometry fixes radius s/2.
  2. Set A(x)=π(2−x)²/8. Reason: A semicircle is half a circle, with the radius squared.
  3. V=(π/8)∫₀²(2−x)²dx=π/3. Reason: Integrate the slice area over its extent.

Turn the base segment into an area, then a volume

A base region gives a slice length, not a slice area. For a vertical base segment between y = f(x) and y = g(x), where f ≥ g on [a,b], set s(x) = f(x) − g(x). A cross section perpendicular to the x-axis has thickness dx. If a triangle has base s and height s/2, its area is ½s(s/2) = s²/4. If the same segment is a semicircle’s diameter, its radius is s/2 and its area is ½π(s/2)² = πs²/8. A circle whose radius is explicitly s instead has area πs².

For each stated shape, the full solid volume is V = ∫ₐᵇ A(x) dx. State the base interval and the shape’s size relation before evaluating. An area formula alone is an ingredient, not a volume calculation: area has square units, dx has length units, and the integral has cubic units. For horizontal slices, use left-to-right length, A(y), dy and y-bounds. A completed base-and-slice diagram should show which actual segment supplies the base or diameter.

CHA-5.BCHA-5.B.2CHA-5.B.3

Two solids sharing one sloping base

The base is 0 ≤ x ≤ 3 cm, 0 ≤ y ≤ 3 − x cm. Sections perpendicular to x are either triangles of height half their base or semicircles using the base segment as diameter. Find both volumes.

  1. The base segment has length s = 3 − x on the specified interval.
  2. Triangle area is (3 − x)²/4; semicircle area is π(3 − x)²/8 because its radius is half the diameter.
  3. The common squared-length integral is ∫₀³(3 − x)² dx = [9x − 3x² + x³/3]₀³ = 9 cm³.
  4. Multiply this integral by the shape coefficient: V_triangle = 9/4 cm³ and V_semicircle = 9π/8 cm³.

Answer and check

The triangular solid has volume 9/4 cm³; the semicircular solid has volume 9π/8 cm³. The same base and bounds do not imply equal volume because the slice areas have different geometric coefficients.

CHA-5.BCHA-5.B.2CHA-5.B.3

Try it from memory

Pause & retrieve

Try it before you peek.

Write your answer and the reason from memory. Then compare with the worked answer. Your self-assessment is a study decision, not an automatically graded score.

Question 1 of 20 self-assessed

Question 1

If a semicircle’s diameter is 4, what is its area?

See every recall question with its answer

These references preserve each prompt and its answer for direct evidence links. Try the interactive questions above before opening the worked reasoning.

Retrieval 1

If a semicircle’s diameter is 4, what is its area?

Worked answer and reason

2π.

Radius is 2, so half-circle area is ½π·2².

Retrieval 2

A triangle has base s and height 2s. What is its area?

Worked answer and reason

s².

Use ½·s·2s.

Catch the tempting mistake

All triangular cross sections have the same area formula in s.
The relation of height to the stated base matters. Equilateral, isosceles, and right triangles require their specified geometry.
Calculator workspace and limits

For calculus, set the angle selector to Radians. This scientific calculator evaluates arithmetic and functions. It does not graph arbitrary functions, find numerical roots, evaluate numerical derivatives, or compute definite integrals. Those tasks need an approved graphing tool; the May 2027 exam permits approved handheld graphing calculators and Bluebook’s built-in Desmos on calculator-required parts. A graph or decimal estimate helps you check a conclusion; your setup, hypotheses, units and justification still do the explaining.

Scientific calculator

This calculator requires JavaScript. Use the physics formula sheets and show your working manually.

Calculation is unavailable without JavaScript.

+ − * / ^ ! · pi · e · sqrt · sin, cos, tan · asin, acos, atan · atan2(y,x) · ln, log · abs · exp · hypot(x,y). Use * between factors. Keep units in your written working.

Put it to work

Explain and apply the mathematics

Try these problems before opening the solutions. Show your setup, the hypotheses behind your method, and what your answer means.

Build a triangular solid from a curved base

No calculator

The planar base is bounded by y = x² and y = 4 on −2 ≤ x ≤ 2. Coordinates are in centimeters. Sections perpendicular to the x-axis are right triangles whose base is the vertical segment in the region and whose height is half that base. The supplied figure shows the actual base region.

The base lies between y equals x squared and y equals 4 on minus 2 to 2 centimeters in x. Triangles are perpendicular to the x axis with height half their base.
Triangular slice geometry
Inspect diagram labels

The diagram keeps its full size here. Focus the view and use the arrow keys, or scroll across it, to inspect every label.

The base lies between y equals x squared and y equals 4 on minus 2 to 2 centimeters in x. Triangles are perpendicular to the x axis with height half their base.

View diagram in a separate tab ↗

(a) Sketch and label a representative triangular cross section at x = 1, including its base and height. Find the general base length s(x), height h(x) and area A(x), and state the slice direction and thickness.

CHA-5.BCHA-5.B.2

(b) Construct the full definite integral for the solid’s volume with its actual bounds. Evaluate it exactly and explain the units. Do not stop at a cross-sectional area formula.

CHA-5.BCHA-5.B.2

(c) A second solid uses the same base and slice direction but triangle height equal to its base instead of half its base. Construct and evaluate its volume integral, then explain the factor change from the first solid.

CHA-5.BCHA-5.B.2

Written working workspace

Drawing is temporarily unavailable. Work on paper if needed, then record your reasoning here.

Saving written working requires JavaScript. Keep your work on paper or in your own notes; the source problem above remains available.

Written working stays in this browser.

A diameter makes a semicircular volume

No calculator

The base lies between y = x and y = 2 − x on 0 ≤ x ≤ 1, with coordinates in centimeters. Sections perpendicular to the x-axis are semicircles whose diameter is the vertical segment between these curves.

The base lies between y equals x and y equals 2 minus x on 0 to 1 centimeter in x. Perpendicular-to-x sections use the vertical segment as semicircle diameter.
Semicircular slice geometry
Inspect diagram labels

The diagram keeps its full size here. Focus the view and use the arrow keys, or scroll across it, to inspect every label.

The base lies between y equals x and y equals 2 minus x on 0 to 1 centimeter in x. Perpendicular-to-x sections use the vertical segment as semicircle diameter.

View diagram in a separate tab ↗

(a) Use the supplied base figure to determine the diameter s(x), radius r(x) and semicircle area A(x). Sketch a correctly proportioned cross section at x = 0.5, labeling its diameter and radius. Explain the factor 1/8 in the area coefficient.

CHA-5.BCHA-5.B.3

(b) Construct and evaluate the full definite integral for the semicircular solid’s volume. State the actual interval, slice thickness and final units.

CHA-5.BCHA-5.B.3

(c) For a different solid on the same base and interval, suppose each cross section is a full circle whose radius, rather than diameter, is s(x). Construct and evaluate its volume integral, and explain its volume ratio to the semicircular solid.

CHA-5.BCHA-5.B.3

Written working workspace

Drawing is temporarily unavailable. Work on paper if needed, then record your reasoning here.

Saving written working requires JavaScript. Keep your work on paper or in your own notes; the source problem above remains available.

Written working stays in this browser.

For the teacher
  • Pair triangle and semicircle problems with the same base region. Ask students to identify the geometric coefficient before integration. Include one directly supplied A(x) to emphasize the general slice principle.

Unit planning and formative guidance →

Glossary and deeper reading · 3 refreshers

These editorial refreshers supplement the reading. Definitions and examples are added guidance; original source wording and recorded answers remain in their original context.

  • Cross section

    A cross section is the planar slice of a solid made by a specified cutting plane. For volume by integration, its area must be expressed as a function of the position along the slicing direction. For example, a square slice with side s(x) has area s(x)². Integrating those areas over the allowed positions yields volume under the method’s assumptions.

    Read more: 8.7 · Cross section →

  • Integral

    Integration can mean accumulating a function over an interval or finding an antiderivative. A definite integral gives a number, while an indefinite integral represents a family of antiderivatives. For example, integrating 2x indefinitely gives x²+C, and integrating it from 0 to 2 gives 4. The Fundamental Theorem of Calculus connects these two operations under its hypotheses.

    Read more: 6.7 · Integral →

  • Definite integral

    A definite integral accumulates a function over a specified interval as a limit of Riemann sums when that limit exists. Its sign includes the function’s sign and the orientation of the limits. For example, the integral of the constant −2 from 0 to 3 is −6, although the geometric area is 6. In a rate model, the result has rate units multiplied by input units.

    Read more: 6.3 · Definite integral →

Search lessons, terms and problems