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Connecting Limits at Infinity and Horizontal Asymptotes

Compare end behavior and relative growth using justified limits, rather than a finite plotting window.

College Board Topic 1.15 · CED p. 47 (PDF p. 52) · CED effective Fall 2020; project course outline 2026–27.

Limits at infinity ask about inputs far out along the domain, rather than near a finite point. If f(x)→L as x→∞ or x→−∞, y=L is a horizontal asymptote for that end. The two ends may have different asymptotes, and a graph may cross a horizontal asymptote.

For rational functions compare highest powers. Divide numerator and denominator by the highest denominator power: (3x²−1)/(2x²+5)=(3−1/x²)/(2+5/x²)→3/2 at either end. A lower-degree numerator tends to 0; a higher-degree numerator may be unbounded or need a different end-behavior description.

Keep signs when roots appear: √(x²+1)/x=√(1+1/x²) for positive x, but equals −√(1+1/x²) for negative x because √(x²)=|x|. Growth comparisons use ratios: ln x/x→0 and x²/eˣ→0 as x→∞. Thus exponential growth eventually dominates this polynomial, which dominates this logarithm. A small-window graph cannot establish “eventually.”

The same comparison works when rate functions are supplied: if a quadratic model has rate 2x and an exponential model has rate eˣ, the established limit 2x/eˣ→0 shows the exponential rate eventually dominates that quadratic rate. Unit 2 explains why these are the corresponding derivative functions.

Let's work through it

  1. To find lim(x→−∞)√(x²+1)/x, write √(x²+1)=|x|√(1+1/x²). Reason: a square root is nonnegative.
  2. For negative x, |x|/x=−1. Reason: the end of the domain determines the sign.
  3. The limit is −1·√1=−1. Reason: 1/x²→0 and the remaining square root is continuous.

Compare values and rates with two different ratios

To compare positive function magnitudes as x grows, divide one by the other. If f(x)/g(x) → 0 as x → +∞, f becomes negligible relative to g. This does not say f itself approaches zero: both functions may increase without bound. It also does not settle their relative rates. A rate is another function, and its comparison needs its own ratio.

At this point in Unit 1, rate functions may be supplied. For f(x) = x² and g(x) = eˣ, suppose their rates are given as r(x) = 2x and s(x) = eˣ. Accept the established limit x²/eˣ → 0. For x > 0, rewrite the rate ratio as r/s = (2/x)(x²/eˣ). Since both factors approach zero, the rate ratio approaches zero too. Thus eˣ eventually dominates x² in value, and its supplied rate eventually dominates 2x. Unit 2 later derives these rate functions; no differentiation rule is needed here.

“Eventually” is a statement about sufficiently large inputs, not every input. A finite graph or table can illustrate a trend but cannot control all far-out behavior. Compare both ratios explicitly, state the positive-input domain, and keep a relative-size conclusion separate from a claim about either function’s own limit.

LIM-2.D.5

Two ratios, two interpretations

For x > 0 let f(x) = x² and g(x) = eˣ, with supplied rate functions r(x) = 2x and s(x) = eˣ. The established function-ratio limit is x²/eˣ → 0 as x → +∞.

  1. The function-ratio limit says that x² becomes small relative to eˣ, although x² itself tends to +∞.
  2. Rewrite r/s = (2/x)(x²/eˣ). The factor 2/x tends to zero and the supplied function-ratio limit is zero, so limit laws give r/s → 0.
  3. At x = 5, f/g = 25/e⁵ ≈ 0.168449 while r/s = 10/e⁵ ≈ 0.0673795. Values and rates use different numerators; matching exponential denominators do not make the ratios equal.
  4. The numerical row illustrates the two comparisons. The supplied established limit and the product-limit argument provide the conclusions about all sufficiently large inputs.

Answer and check

Both x²/eˣ and 2x/eˣ tend to zero. The exponential model eventually dominates this quadratic in value and in supplied rate, while the quadratic and its rate can still tend to +∞.

LIM-2.D.5

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Question 1 of 20 self-assessed

Question 1

What is the horizontal asymptote of (5x+2)/(2x−1)?

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Retrieval 1

What is the horizontal asymptote of (5x+2)/(2x−1)?

Worked answer and reason

y=5/2 at both ends.

Divide by x or compare equal-degree leading coefficients.

Retrieval 2

If f(x)/g(x)→0 for positive-growing functions, which grows faster eventually?

Worked answer and reason

g grows faster in the ratio sense.

f becomes small compared with g; absolute sizes at one input do not decide the limit.

Catch the tempting mistake

A horizontal asymptote can never be crossed.
The asymptote describes end behavior; a graph may cross it at finite inputs.
Calculator workspace and limits

For calculus, set the angle selector to Radians. This scientific calculator evaluates arithmetic and functions. It does not graph arbitrary functions, find numerical roots, evaluate numerical derivatives, or compute definite integrals. Those tasks need an approved graphing tool; the May 2027 exam permits approved handheld graphing calculators and Bluebook’s built-in Desmos on calculator-required parts. A graph or decimal estimate helps you check a conclusion; your setup, hypotheses, units and justification still do the explaining.

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Compare a model and its supplied rate separately

Graphing calculator required

For x > 0, f(x) = 10x² and g(x) = eˣ. Their rate functions are supplied as r(x) = 20x and s(x) = eˣ; do not derive them. You may use the established limit lim(x → +∞) x²/eˣ = 0 and ordinary limit laws. No L’Hôpital rule, series expansion or later derivative method is needed.

For 4 ≤ x ≤ 12, the ratios 10x²/eˣ and 20x/eˣ decrease toward zero. At x = 5 the first ratio is about 1.684 while the second is about 0.674.
A finite view can show different comparisons for function values and supplied rates. The stated limits, rather than this finite window, justify the eventual conclusions.
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For 4 ≤ x ≤ 12, the ratios 10x²/eˣ and 20x/eˣ decrease toward zero. At x = 5 the first ratio is about 1.684 while the second is about 0.674.

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(a) Use the established limit to calculate lim(x → +∞) f(x)/g(x). Interpret the result as a comparison of the function magnitudes and explain why it does not mean f(x) tends to zero.

LIM-2.D.5

(b) Rewrite r(x)/s(x) as a product involving x²/eˣ, then use limit laws to calculate its limit as x → +∞. Interpret it as a comparison of the supplied rate magnitudes, preserving the distinction between the rate functions and the original functions.

LIM-2.D.5

(c) Use both limit results to summarize the eventual relative magnitudes of the two functions and the two supplied rates. At x = 5, calculate both ratios and state which function and which rate are larger there. Explain why a finite table or the supplied finite graph cannot by itself prove either eventual limit.

LIM-2.D.5

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What does a vanishing ratio say?

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For positive x, F(x) = 10x² and G(x) = eˣ have supplied rates R(x) = 20x and S(x) = eˣ. It is established that F/G → 0 and R/S → 0 as x → +∞.

(a) Choose the conclusion justified by both established limits. Distinguish an eventual relative comparison from a statement about each numerator’s own limit or about every positive input.

LIM-2.D.5

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For the teacher
  • Show both positive and negative end behavior for a radical quotient.
  • Compare growth using ratios and a table with expanding input ranges, while distinguishing numerical evidence from a proof.

Unit planning and formative guidance →

Glossary and deeper reading · 8 refreshers

These editorial refreshers supplement the reading. Definitions and examples are added guidance; original source wording and recorded answers remain in their original context.

  • Limit

    A limit describes the value approached by outputs as inputs approach a specified target or grow without bound. For an input approaching a finite target, its value at that exact input does not determine the limit. For example, (x²−1)/(x−1) approaches 2 as x approaches 1 even though the original expression is undefined at 1. A finite two-sided limit requires the left and right approaches to agree.

    Read more: 1.2 · Limit →

  • Domain

    The domain of a function is the set of inputs for which the function is defined. An expression and its context can both restrict the allowed inputs. For example, the real function f(x)=1/(x−2) has domain all real numbers except 2. For a model of elapsed time, a sensible domain may also require t≥0.

  • Rational function

    A rational function is a quotient of two polynomials. Its domain excludes inputs that make the original denominator zero. For example, (x²−1)/(x−1) agrees with x+1 away from x=1, but remains undefined there. Canceling a common factor does not automatically restore an excluded input.

  • Exponential growth and decay

    An exponential growth or decay model makes a quantity’s instantaneous rate proportional to the quantity itself. The differential equation y′=ky gives y=Ceᵏˣ, with positive k describing growth and negative k describing decay for positive y. For example, a population with a constant relative growth rate doubles in equal time intervals. Its relative rate stays constant, while its absolute rate changes with the amount present.

    Read more: 7.8 · Exponential growth and decay →

  • Polynomial

    A polynomial in one variable is a finite sum of constant multiples of nonnegative integer powers of that variable. The degree is the highest exponent with a nonzero coefficient. For example, 2x³−x+5 is a polynomial of degree 3. Expressions containing 1/x or √x are not polynomials in x.

  • Function

    A mathematical function assigns exactly one output to each input in its domain. Inputs can share an output, but one input cannot have two different outputs. For example, f(x)=x² assigns the output 9 to both 3 and −3. Function notation names the rule and its input; f(3) means the output when the input is 3.

  • Derivative

    A derivative gives the instantaneous rate of change of a function with respect to its input. At a point, it is the finite limit of the difference quotient when that limit exists. For example, the derivative of x² is 2x, so the tangent slope at x=3 is 6. A derivative function collects those rates across the inputs where the function is differentiable.

    Read more: 2.2 · Derivative →

  • Limit laws

    Limit laws allow limits of sums, products, and suitable quotients to be assembled from the limits of their parts. The component limits must exist as required, and a quotient law needs a nonzero denominator limit. For example, if f approaches 2 and g approaches 3, then f+g approaches 5 and fg approaches 6. Direct substitution into a quotient with denominator limit 0 is not justified by the quotient limit law.

    Read more: 1.5 · Algebraic properties of limits →

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