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Light

Original textbook reading.

Enrichment beyond the AP course.

This original chapter is extra exploration beyond the supplied AP Physics 1 course. Keep it if you're curious about where these ideas go next.

Electromagnetic waves, including light, can propagate through vacuum without a material medium. Mechanical waves such as sound require a medium.

Light has wave properties and exchanges energy in discrete quanta called photons. A photon is not a tiny object following a sinusoidal trajectory. In an electromagnetic wave, the fields vary in space and time.

Wave speed, frequency, and wavelength are related by v = fλ. In vacuum, all electromagnetic waves have speed c.

Explore the figure

Figure 9.3.1 Refraction at an Air–Water Boundary

A ray enters water from air and bends toward the dotted normal; the refracted angle θ₂ is smaller than the incident angle θ₁.
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Angle of Refraction

On entering water from air, the pictured ray bends toward the dotted normal. The refracted angle θ₂ is therefore smaller than the incident angle θ₁; both angles are measured from the normal.

Dotted Line?

This dotted line helps us in determining the angles for the incoming and refracting light rays as it passes from air into water.

For light, the velocity will always be a factor of the constant c, which is the speed of light in a vacuum.

c=2.998×108m/s

The actual speed of light in some medium (i.e. not a vacuum) is calculated using the equation:

c is the constant, v is the speed of light in some medium, and n is that medium’s refractive indexⓘ.

This idea of a refractive index is what causes refraction of light. The refraction of light is the change in the angle of light as it passes from one medium to another. This is why when you put a pencil in water; it appears ‘broken’ at the water’s surface.

Snell’s Law↗ is used for this situation and it states:

sinθ1sinθ2=n2n1 (Equation 9.3.3)

The refractive indices refer to the two media, and both angles in Snell’s law are measured from the normal to the interface.

Another aspect of light is color. The term light refers to a specific type of electromagnetic radiation. This electromagnetic radiation refers to any wave-particle instance of a photon. The only reason that we see this radiation as light is due to the wavelength of that photon. A diagram of the electromagnetic spectrumⓘ is shown in the figure.

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Figure 9.3.2 Electromagnetic Spectrum

Increasing wavelength runs from gamma rays through X-rays, ultraviolet, visible light, infrared, microwaves, and radio waves. The visible-band strip runs from violet near 400 nm to red near 700 nm as wavelength increases.

Wavelength increases from left to right. In the visible band, violet has shorter wavelength than red. The category overview is schematic; the visible strip is a separate enlargement. Electromagnetic spectrum.

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Boundaries

As it is kind of hard to read, a few approximate boundaries will follow (all are in m):

Approximate X-ray wavelengths: 10⁻¹¹ to 10⁻⁸ m.

Approximate visible wavelengths: 4 × 10⁻⁷ to 7 × 10⁻⁷ m.

Microwaves occupy an approximate range from 10⁻³ to 1 m; category boundaries vary by convention.

Small Range

Along this whole wavelength range, visible light only covers a small fraction of it.

The small range of around 400-700nm is the only part that we can see of this visible light spectrum. There are cameras that will take other wavelengths and convert them into visible light, allowing us to ‘see’ the other parts of the spectrum. That is actually what a thermal camera does. Heat generates infrared light, and the thermal cameras detect that light and convert it into video we can see.

The wavelength of light is dependent on the light’s frequency. We covered before that light’s velocity varies depending on the medium it’s in. Typically, you will encounter light in air, which has a refractive index of 1.0003. This means that we can approximate the speed of light in air to be equal to c.

Therefore, we can calculate the light’s wavelength as:

The table in the next column is a list of different mediums with their respective refractive indices which you can use for referencing when encountering problems dealing with light refraction.

Table 9.3.1: Refractive Indexes of Different Mediums

Table9.3.1 — details in the accompanying text.

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Example Problem 9.3.1

Example Problem 9.3.1
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The Period

The waves take 2.54 seconds to travel from the Earth to the moon then back to the Earth. How can we use that to solve for distance? How fast does light travel in space? How are those related? Hmmmmm....

A radar system that broadcasts electromagnetic radiation with λ=5cm attempts to determine the distance from the earth to the moon. They bounce radar waves off of the moon and determine the time it takes for them to return. If that time is 2.54seconds, determine the distance to the moon. Also determine the frequency of the radar used.

Step 1. Determine the length the light traveled

As we can assume that the light is traveling at c (which we treat as the velocity), then the distance it travels is given by:

x=c⋅t

x=(2.998×108m/s)⋅2.54s

x=7.615×108m

Step 2. Approximate the distance to the moon

The path that the radar waves took was from the radar center to the moon and back. This means that the distance it traveled was twice the distance from the earth to the moon. Therefore, the distance from the earth to the moon is approximated by halving our answer from step 1:

D=12(7.615×108m)

D=3.807×108m

Step 3. Determine the frequency of the radar

The equation we use for this step is Equation 9.3.4. As we know that the wavelength is 5cm , or 0.05m, we get:

c=f⋅λ

2.998×108m/s=f(0.05m)

f=5.996×109Hz

f=5.996GHz

A photon of frequency f carries energy E = hf. For N photons of that frequency, total energy is Nhf. Total beam energy therefore depends on both photon frequency and photon number.

This lead to the Planck-Einstein equation:

In this equation, f is the wave’s frequency, and h is the Planck Constantⓘ, 6.626×10-34J⋅s. This can be re-written by using the definition of frequency:

E=h⋅cλ

In the photoelectric effect, incident light can eject electrons from a material. The work function is the minimum photon energy needed for ordinary single-photon emission from that surface; K_max = hf − φ when hf ≥ φ.

A model carbon surface is assigned a work function 7.686 × 10⁻¹⁹ J. Find the threshold photon frequency and corresponding maximum wavelength for photoelectric emission. Classify this radiation.

Step 1. Determine the frequency of the light needed to ionize carbon

E=h⋅f

7.686×10-19J=(6.626×10-34J⋅s)⋅f

f=1.160×1015Hz

f=1.160PHz

Step 2. Determine the light’s wavelength

λ=cf

λ=2.998×108m/s1.16×1015Hz

λ=2.58×10-7m

λ=258nm

Step 3. Figure out what type of light it is.

That wavelength corresponds to electromagnetic radiation in the realm of ultraviolet light.

Pause & recall

Pop Quiz 9.3.1 Light Waves

Question 1 of 5 · 0 correct

Extra exploration · Read the worked solution

If a radio station broadcasts on station 101.3FM, that equates to 101.3MHz. What is the wavelength of this station's broadcast?

Select one answer.
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Question 1

If a radio station broadcasts on station 101.3FM, that equates to 101.3MHz. What is the wavelength of this station's broadcast?

  1. 1.01m

  2. 2.14m

  3. 2.96m

  4. 3.03m

Separate worked answer

Question 2

If the sun were to emit a solar flare, how long would the light take to reach the earth? The distance from the earth to the sun is approximately 1.496×1011m.

  1. 6min54s

  2. 7min42s

  3. 8min19s

  4. 9min8s

Separate worked answer

Question 3

The nearest star to earth, Proxima Centauri, is 4.243 light years away. That means it takes its light 4.243 years to reach earth. Determine the distance from earth to that star in km.

  1. 4.014×1013km

  2. 4.243×1013km

  3. 5.085×1013km

  4. 6.741×1013km

Separate worked answer

Question 4

Sound travels at 340.29m/s If you see lightning strike near you, and you hear the accompanying thunder after 5 seconds, how far away is the strike?

  1. 1.25km

  2. 1.70km

  3. 2.04km

  4. 2.25km

Separate worked answer

Question 5

For an object receding along the line of sight, emitted visible spectral features shift toward which end of the visible spectrum?

  1. Red

  2. Yellow

  3. Green

  4. Blue

Separate worked answer

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IMG 0092 cropped — details in the accompanying text.
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Reviewed physics notes (12)

These corrections keep the original lesson’s purpose while fixing errors in the source edition.

  • Removes the suggestion that light “prefers” a medium as a physical mechanism. — Reference 1
  • Photons do not move along wave-shaped paths. — Reference 1
  • Corrects the asserted speed of a photon moving “along its wave.” — Reference 1
  • The normal convention is essential to the later diagrams. — Reference 1
  • Separates energy per photon from total energy and removes the claim of photon paths along a wave. — Reference 1
  • Adds the emission threshold and correct surface-work-function terminology. — Reference 1
  • A surface work function is not the atomic ionization energy of carbon; the source’s numerical threshold is retained as a stipulated model value. — Reference 1
  • The depicted change in ray angle is refraction, not diffraction. — Reference 1
  • The displayed X-ray range is overly narrow; boundaries are approximate. — Reference 1
  • The source’s 10⁻⁶ to 10⁻⁵ m is infrared rather than visible light. — Reference 1
  • The source’s 0.01–0.1 m range is only a subset of microwaves, and “Micowaves” is misspelled. — Reference 1
  • Recession means redshift, but an arbitrary object does not necessarily appear literally red. — Reference 1

About this edition and its source ↗

Glossary and deeper reading · 12 refreshers

These editorial refreshers supplement the reading. Definitions and examples are added guidance; original source wording and recorded answers remain in their original context.

  • Electromagnetic wave

    An electromagnetic wave contains oscillating electric and magnetic fields that transport energy. In the plane-wave vacuum model, both fields are perpendicular to each other and to the propagation direction. For example, visible light and radio waves can both travel through empty space.

    Read more: Electromagnetic wave in detail →

  • Wave

    A wave is a propagating disturbance that can transfer energy without transporting the medium as a whole. Mechanical waves require a material medium, while electromagnetic waves can propagate through vacuum. For example, a pulse travels along a rope while individual rope segments move locally around their equilibrium positions.

    Read more: Mechanical waves →

  • Photon

    A photon is a quantum of electromagnetic radiation with energy proportional to its frequency. It has zero rest mass and no electric charge but carries energy and momentum. For example, increasing light’s frequency increases the energy of each photon, while increasing the number of same-frequency photons increases the total energy.

  • Frequency

    Frequency is the number of complete repeating cycles per unit time. It is measured in hertz, meaning cycles per second, and is the reciprocal of the period. For example, a vibrating string with a higher frequency produces more cycles each second.

    Read more: Frequency in detail →

  • Wavelength

    Wavelength is the spatial distance between neighboring points at the same phase of a periodic wave. It connects propagation speed and frequency through speed equal to frequency times wavelength. For example, neighboring crests of a sinusoidal water wave are separated by one wavelength.

    Read more: Parts of a wave →

  • Velocity

    Velocity describes how position changes with time and includes direction. Instantaneous velocity describes one moment, while average velocity is displacement divided by elapsed time. For example, a car turning a corner can change velocity while maintaining the same speed.

    Read more: Variables of motion →

  • Refractive index

    Refractive index is the ratio of light’s speed in vacuum to its speed in the material at the relevant frequency. It is dimensionless and can depend on wavelength. For example, glass usually has a larger refractive index than air, so visible light travels more slowly through the glass.

    Read more: Refractive index in detail →

  • Refraction

    Refraction is a change in wave propagation at a boundary where wave speed changes. For light entering a new medium, frequency stays fixed while speed and wavelength can change, and the direction generally bends unless incidence is normal. For example, a light ray entering water obliquely from air bends toward the normal.

    Read more: Refraction in detail →

  • Snell’s law

    Snell’s law relates the incidence and refraction angles to the refractive indices of two media. Both angles are measured from the normal to the boundary, rather than from the surface. For example, entering a higher-index material at oblique incidence bends a light ray toward the normal.

    Read more: Snell’s law in detail →

  • Electromagnetic spectrum

    The electromagnetic spectrum is the continuous range of electromagnetic-wave frequencies and wavelengths. Increasing frequency corresponds to decreasing vacuum wavelength, from radio toward gamma-ray wavelengths. For example, infrared light has a longer wavelength and lower frequency than visible violet light.

  • Heat

    Heat is energy transferred between systems because of a temperature difference. It describes a transfer rather than a substance or energy store contained in an object. For example, when a warmer mug transfers energy to a cooler hand, the mug loses internal energy and the hand gains it.

    Read more: Heat in detail →

  • Planck’s constant

    Planck’s constant relates the energy of a photon to its frequency. It also sets the scale connecting particle momentum to de Broglie wavelength. For example, two photons of different frequencies have energies in the same ratio as their frequencies because the constant is the same for both.

    Read more: Planck’s constant in detail →

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