Access this content offline
Omniguides
Skip to the reading

Refraction

Connect refraction with index, unchanged frequency, and the conditions for total internal reflection.

AP Physics 2 Topic 13.3 · College Board CED printed p. 98, 99 / PDF p. 105, 106 · See this topic in the course outline

A boundary changes the speed light can travel. At an oblique angle, that speed change bends the transmitted path. Use the normal, keep frequency fixed, and check whether a transmitted ray can exist.

Before you start
  • Sine and inverse sine in degrees
  • Wave speed v = fλ
  • Reflection law

Refraction comes from a speed change

Light changes speed when it enters a different transparent medium. At an oblique boundary the direction of its transmitted ray generally changes too; this is refraction. The refractive index is n=c/vn=c/v, where c is the vacuum light speed and v is the light speed in the material. A higher n means slower light. Use c≈3.00×108  m/sc\approx3.00\times10^8\;\mathrm{m/s} in these calculations.

At a stationary boundary the frequency stays fixed by the source. In the wave-speed relationship, v=fλv=f\lambda, f denotes frequency (cycles per second, in Hz) and λ denotes wavelength (distance between successive equal-phase fronts, in metres). This frequency f is different from the focal-length f used in mirror and lens equations. With frequency fixed, a lower speed means a shorter wavelength, not a lower frequency. At normal incidence the direction stays straight even though speed and wavelength change. A refracted-ray diagram should show both media, their indices, the boundary, a normal, and arrows crossing it.

Use Snell’s law with angles from the normal

Snell’s law is n1sin⁡θ1=n2sin⁡θ2n_1\sin\theta_1=n_2\sin\theta_2. Medium 1 is where the incident ray travels; medium 2 is where the transmitted ray would travel. Both angles are measured from the same interface normal. For lower-to-higher index, the ray bends toward the normal (smaller θ). For higher-to-lower index, a transmitted ray bends away from the normal (larger θ). At normal incidence θ₁ = 0 gives θ₂ = 0: no directional bending.

Snell predictions; angles to the normal
n₁ → n₂θ₁θ₂Direction
1.00 → 1.5030.0°19.5°Toward normal
1.50 → 1.0030.0°48.6°Away from normal
1.00 → 1.500°0°Straight, but slower

For a parallel-sided slab surrounded by the same medium, Snell’s law at the second surface restores the original direction, but the exiting ray can be shifted sideways. A partly reflected ray can coexist with the refracted ray at a boundary; refraction does not require all light energy to be transmitted.

Check the two conditions for total internal reflection

Total internal reflection is possible only for light approaching a lower-index medium from a higher-index medium, n1>n2n_1>n_2. Increase the incident angle and the transmitted angle grows until it reaches 90°. At this critical angle the transmitted ray runs along the interface. Setting sin θ₂ = 1 in Snell’s law gives θc=sin⁡−1(n2/n1)\theta_c=\sin^{-1}(n_2/n_1).

For θ₁ > θ_c there is no real transmitted-ray angle: Snell would require sin θ₂ > 1. In the ideal lossless geometric model, all incident light reflects back into medium 1 and no light is transmitted into medium 2. Do not draw an impossible bent ray. At θ₁ = θ_c the boundary case is a grazing transmitted ray; total internal reflection is the beyond-critical case. Lower-to-higher index has no critical angle for this purpose, no matter how large its incident angle is.

For n₁ = 1.50 and n₂ = 1.00, θ_c = 41.8°. An internal 30° ray transmits and bends away; a 41.8° ray is the grazing limit; a 50° ray reflects entirely in the ideal model. A real device can have absorption or surface imperfections; “total” here refers to the ideal reflection-versus-transmission boundary condition.

Find speed and refraction angle

A 600 nm vacuum-wavelength beam enters a material of n = 1.50 from air (n = 1.00) at 40.0° to the normal. Find speed, transmitted angle, and wavelength in the material.

  1. Choose air as medium 1 and the material as medium 2. v = c/n = 2.00 × 10⁸ m/s.

    Why this step? The refractive index relates speed to the vacuum value.

  2. sin θ₂ = (1.00/1.50) sin 40.0° = 0.4285, so θ₂ = 25.4°.

    Why this step? Snell uses normal angles and the inverse sine recovers the transmitted angle.

  3. The frequency remains fixed, so λ_material = λ_vacuum/n = 400 nm.

    Why this step? Speed changes without a source-frequency change.

  4. θ₂ is smaller than θ₁, as expected for increasing index.

    Why this step? The direction trend is a physical check on arithmetic and index order.

Answer and check

2.00 × 10⁸ m/s; 25.4° to the normal; 400 nm.

Reject an impossible transmitted ray

Light in a liquid of n = 1.40 strikes an air boundary (n = 1.00) at 50.0° to the normal. Determine the critical angle and the ray’s fate.

  1. The ray approaches a lower-index medium, so a critical angle exists. θ_c = sin⁻¹(1.00/1.40) = 45.6°.

    Why this step? Check index order before applying a critical-angle formula.

  2. 50.0° > 45.6°, so the incident ray undergoes total internal reflection. Its reflected angle is 50.0° to the normal.

    Why this step? Beyond the critical angle, there is no propagating transmitted ray in the ideal geometric model.

  3. Trying Snell gives sin θ₂ = 1.40 sin 50.0° = 1.072, which cannot be the sine of a real angle.

    Why this step? The failed transmitted-angle calculation is consistent with the physical boundary, not a calculator error.

Answer and check

θ_c = 45.6°; all light reflects in the ideal lossless model, at 50.0°.

Make the model respond

Focused Physics 2 model

Refraction and thin-lens ray models

Predict first. Choose a model. Predict the direction of refraction or whether the lens image is real or virtual.

n₁ sin θ₁ = n₂ sin θ₂; θreflection = θ₁; sin θc = n₂/n₁ when n₁ > n₂

Refraction and thin-lens ray models: schematicGreen incident ray arrives from medium 1. Brown reflected ray makes the same angle to the dashed normal. The blue transmitted ray enters medium 2 when Snell’s law allows it. Under total internal reflection there is no propagating transmitted ray; the evanescent field is outside this ray model. Ray widths do not indicate intensity.n₁ = 1n₂ = 1.5normalRefraction at a flat boundary
Green incident ray arrives from medium 1. Brown reflected ray makes the same angle to the dashed normal. The blue transmitted ray enters medium 2 when Snell’s law allows it. Under total internal reflection there is no propagating transmitted ray; the evanescent field is outside this ray model. Ray widths do not indicate intensity.

On a narrow screen, scroll within a figure to read its labels. The table and explanation provide the same physics in text.

Incident angle40 °
Transmitted angle25.37 °
Critical angleNone for this direction

θ₂ = 25.37°. The transmitted ray bends toward the normal.

Read the model data and comparisons
Selected-state values. SI units are shown explicitly; display controls may use named SI prefixes.
QuantityValueUnitMeaning or limit
Incident-medium index n₁1
Transmitted-medium index n₂1.5
Incident angle40°All angles are from the normal
Reflected angle40°
Transmitted angle25.37°
Critical anglenot applicable (n₁ ≤ n₂)°

Indices set wave speed v = c/n and wavelength λ = v/f in each medium; frequency stays constant across the boundary. For oblique transmission, a larger index gives a smaller angle to the normal. At normal incidence, direction does not change even when the index changes; speed and wavelength still change with index. Total internal reflection requires incidence from higher to lower index and an angle above the critical angle. At exactly the critical angle, the refracted ray is tangent to the boundary. This diagram includes reflection direction but does not calculate reflected or transmitted intensities.

Assumptions and limits. Geometric optics, flat interface, homogeneous transparent media, positive real refractive indices, incidence from medium 1 to medium 2. Angles are from the normal, not the surface. No absorption, Fresnel intensity coefficients, polarization, or curved surfaces.

Try it from memory

Write your answer and reason before opening the worked answer. Your self-assessment is a study decision; it is not an automatically graded score.

Question 1

Light enters higher-index glass at normal incidence. What changes: direction, speed, frequency, or wavelength?

Worked answer and reason

Direction and frequency remain unchanged. Speed and wavelength decrease.

Normal incidence prevents directional bending, but the material speed differs and the source fixes frequency.

Question 2

A ray is 70° to a flat surface. Which incidence angle belongs in Snell’s law?

Worked answer and reason

20° to the normal.

The normal is perpendicular to the surface.

Question 3

Can an air-to-glass ray undergo total internal reflection at 85° incidence?

Worked answer and reason

No, because it is entering a higher-index medium. The transmitted ray bends toward the normal.

Total internal reflection needs higher-to-lower index as well as a beyond-critical angle.

Question 4

At the critical angle, is the transmitted ray normal to the surface, along it, or absent in the limiting ray diagram?

Worked answer and reason

Along the surface, at 90° to the normal. Beyond the critical angle the transmitted ray is absent.

The critical condition follows by setting the transmitted-angle sine equal to one.

JavaScript enables saved drafts and self-assessment. You can always work on paper.

Catch the tempting mistake

Light changes frequency when it enters glass.
A stationary boundary keeps the source frequency fixed; speed and wavelength change.
Any sufficiently steep incidence can cause total internal reflection.
The ray must first be going from higher index to lower index.
An inverse-sine input above one means round the angle to 90°.
It means no real transmitted ray exists under the stated conditions.

Put it to work

Give the physical reason as well as the calculation. The worked solutions are on a separate page.

  • Problem 5 · verbal and mathematical
  • Problem 6 · derivation and boundary-case ray diagrams
  • Problem 9 · experimental design and graph
  • Problem 11 · data graph, experimental design, and prediction
Scientific calculator workspace

Keep intermediate precision and report units. This calculator supports arithmetic and elementary functions.

Scientific calculator

This calculator requires JavaScript. Use the physics formula sheets and show your working manually.

Calculation is unavailable without JavaScript.

+ − * / ^ ! · pi · e · sqrt · sin, cos, tan · asin, acos, atan · atan2(y,x) · ln, log · abs · exp · hypot(x,y). Use * between factors. Keep units in your written working.

For the teacher
  • Have learners identify medium 1 from the incoming arrow, rather than from table order.
  • Use a semicircular block so the incoming ray can enter normally at its curved surface; this isolates refraction at the flat face.
  • Check the two TIR conditions in words before calculating a critical angle.

Unit planning and inquiry guidance →

Source objectives and scope
  • 13.3.A — Describe the refraction of light between two media.

Suggested skills are teaching guidance. The course applies all science practices across its objectives.

Science references for this teaching
Glossary and deeper reading · 6 refreshers

These editorial refreshers supplement the reading. Definitions and examples are added guidance; original source wording and recorded answers remain in their original context.

  • Frequency

    Frequency is the number of complete repeating cycles per unit time. It is measured in hertz, meaning cycles per second, and is the reciprocal of the period. For example, a vibrating string with a higher frequency produces more cycles each second.

    Read more: Period, frequency, and wavelength →

  • Refractive index

    Refractive index is the ratio of light’s speed in vacuum to its speed in the material at the relevant frequency. It is dimensionless and can depend on wavelength. For example, glass usually has a larger refractive index than air, so visible light travels more slowly through the glass.

  • Wave

    A wave is a propagating disturbance that can transfer energy without transporting the medium as a whole. Mechanical waves require a material medium, while electromagnetic waves can propagate through vacuum. For example, a pulse travels along a rope while individual rope segments move locally around their equilibrium positions.

    Read more: Wave in detail →

  • Wavelength

    Wavelength is the spatial distance between neighboring points at the same phase of a periodic wave. It connects propagation speed and frequency through speed equal to frequency times wavelength. For example, neighboring crests of a sinusoidal water wave are separated by one wavelength.

    Read more: Wavelength in detail →

  • Reflection

    Reflection occurs when a wave returns from a boundary into the region from which it arrived. For a light ray at a surface, the reflection angle equals the incidence angle when both are measured from the local normal. For example, a smooth mirror produces an orderly image while a rough surface scatters reflected rays in many directions.

    Read more: Reflection in detail →

  • Critical angle

    The critical angle is the incidence angle at which the refracted ray would travel along the boundary toward a lower-index medium. At larger incidence angles the ideal model gives total internal reflection. For example, a ray leaving water for air can refract below the critical angle but undergo total internal reflection above it.

Search lessons, terms and problems