Refraction
Connect refraction with index, unchanged frequency, and the conditions for total internal reflection.
AP Physics 2 Topic 13.3 · College Board CED printed p. 98, 99 / PDF p. 105, 106 · See this topic in the course outline
A boundary changes the speed light can travel. At an oblique angle, that speed change bends the transmitted path. Use the normal, keep frequency fixed, and check whether a transmitted ray can exist.
Before you start
- Sine and inverse sine in degrees
- Wave speed v = fλ
- Reflection law
Refraction comes from a speed change
Light changes speed when it enters a different transparent medium. At an oblique boundary the direction of its transmitted ray generally changes too; this is refraction. The refractive index is , where c is the vacuum light speed and v is the light speed in the material. A higher n means slower light. Use in these calculations.
At a stationary boundary the frequency stays fixed by the source. In the wave-speed relationship, , f denotes frequency (cycles per second, in Hz) and λ denotes wavelength (distance between successive equal-phase fronts, in metres). This frequency f is different from the focal-length f used in mirror and lens equations. With frequency fixed, a lower speed means a shorter wavelength, not a lower frequency. At normal incidence the direction stays straight even though speed and wavelength change. A refracted-ray diagram should show both media, their indices, the boundary, a normal, and arrows crossing it.
Use Snell’s law with angles from the normal
Snell’s law is . Medium 1 is where the incident ray travels; medium 2 is where the transmitted ray would travel. Both angles are measured from the same interface normal. For lower-to-higher index, the ray bends toward the normal (smaller θ). For higher-to-lower index, a transmitted ray bends away from the normal (larger θ). At normal incidence θ₁ = 0 gives θ₂ = 0: no directional bending.
| n₁ → n₂ | θ₁ | θ₂ | Direction |
|---|---|---|---|
| 1.00 → 1.50 | 30.0° | 19.5° | Toward normal |
| 1.50 → 1.00 | 30.0° | 48.6° | Away from normal |
| 1.00 → 1.50 | 0° | 0° | Straight, but slower |
For a parallel-sided slab surrounded by the same medium, Snell’s law at the second surface restores the original direction, but the exiting ray can be shifted sideways. A partly reflected ray can coexist with the refracted ray at a boundary; refraction does not require all light energy to be transmitted.
Check the two conditions for total internal reflection
Total internal reflection is possible only for light approaching a lower-index medium from a higher-index medium, . Increase the incident angle and the transmitted angle grows until it reaches 90°. At this critical angle the transmitted ray runs along the interface. Setting sin θ₂ = 1 in Snell’s law gives .
For θ₁ > θ_c there is no real transmitted-ray angle: Snell would require sin θ₂ > 1. In the ideal lossless geometric model, all incident light reflects back into medium 1 and no light is transmitted into medium 2. Do not draw an impossible bent ray. At θ₁ = θ_c the boundary case is a grazing transmitted ray; total internal reflection is the beyond-critical case. Lower-to-higher index has no critical angle for this purpose, no matter how large its incident angle is.
For n₁ = 1.50 and n₂ = 1.00, θ_c = 41.8°. An internal 30° ray transmits and bends away; a 41.8° ray is the grazing limit; a 50° ray reflects entirely in the ideal model. A real device can have absorption or surface imperfections; “total” here refers to the ideal reflection-versus-transmission boundary condition.
Find speed and refraction angle
A 600 nm vacuum-wavelength beam enters a material of n = 1.50 from air (n = 1.00) at 40.0° to the normal. Find speed, transmitted angle, and wavelength in the material.
Choose air as medium 1 and the material as medium 2. v = c/n = 2.00 × 10⁸ m/s.
Why this step? The refractive index relates speed to the vacuum value.
sin θ₂ = (1.00/1.50) sin 40.0° = 0.4285, so θ₂ = 25.4°.
Why this step? Snell uses normal angles and the inverse sine recovers the transmitted angle.
The frequency remains fixed, so λ_material = λ_vacuum/n = 400 nm.
Why this step? Speed changes without a source-frequency change.
θ₂ is smaller than θ₁, as expected for increasing index.
Why this step? The direction trend is a physical check on arithmetic and index order.
Answer and check
2.00 × 10⁸ m/s; 25.4° to the normal; 400 nm.
Reject an impossible transmitted ray
Light in a liquid of n = 1.40 strikes an air boundary (n = 1.00) at 50.0° to the normal. Determine the critical angle and the ray’s fate.
The ray approaches a lower-index medium, so a critical angle exists. θ_c = sin⁻¹(1.00/1.40) = 45.6°.
Why this step? Check index order before applying a critical-angle formula.
50.0° > 45.6°, so the incident ray undergoes total internal reflection. Its reflected angle is 50.0° to the normal.
Why this step? Beyond the critical angle, there is no propagating transmitted ray in the ideal geometric model.
Trying Snell gives sin θ₂ = 1.40 sin 50.0° = 1.072, which cannot be the sine of a real angle.
Why this step? The failed transmitted-angle calculation is consistent with the physical boundary, not a calculator error.
Answer and check
θ_c = 45.6°; all light reflects in the ideal lossless model, at 50.0°.
Make the model respond
Focused Physics 2 model
Refraction and thin-lens ray models
Predict first. Choose a model. Predict the direction of refraction or whether the lens image is real or virtual.
n₁ sin θ₁ = n₂ sin θ₂; θreflection = θ₁; sin θc = n₂/n₁ when n₁ > n₂
On a narrow screen, scroll within a figure to read its labels. The table and explanation provide the same physics in text.
θ₂ = 25.37°. The transmitted ray bends toward the normal.
Read the model data and comparisons
| Quantity | Value | Unit | Meaning or limit |
|---|---|---|---|
| Incident-medium index n₁ | 1 | ||
| Transmitted-medium index n₂ | 1.5 | ||
| Incident angle | 40 | ° | All angles are from the normal |
| Reflected angle | 40 | ° | |
| Transmitted angle | 25.37 | ° | |
| Critical angle | not applicable (n₁ ≤ n₂) | ° |
Indices set wave speed v = c/n and wavelength λ = v/f in each medium; frequency stays constant across the boundary. For oblique transmission, a larger index gives a smaller angle to the normal. At normal incidence, direction does not change even when the index changes; speed and wavelength still change with index. Total internal reflection requires incidence from higher to lower index and an angle above the critical angle. At exactly the critical angle, the refracted ray is tangent to the boundary. This diagram includes reflection direction but does not calculate reflected or transmitted intensities.
Assumptions and limits. Geometric optics, flat interface, homogeneous transparent media, positive real refractive indices, incidence from medium 1 to medium 2. Angles are from the normal, not the surface. No absorption, Fresnel intensity coefficients, polarization, or curved surfaces.
Try it from memory
Write your answer and reason before opening the worked answer. Your self-assessment is a study decision; it is not an automatically graded score.
Question 1
Light enters higher-index glass at normal incidence. What changes: direction, speed, frequency, or wavelength?
Worked answer and reason
Direction and frequency remain unchanged. Speed and wavelength decrease.
Normal incidence prevents directional bending, but the material speed differs and the source fixes frequency.
Question 2
A ray is 70° to a flat surface. Which incidence angle belongs in Snell’s law?
Worked answer and reason
20° to the normal.
The normal is perpendicular to the surface.
Question 3
Can an air-to-glass ray undergo total internal reflection at 85° incidence?
Worked answer and reason
No, because it is entering a higher-index medium. The transmitted ray bends toward the normal.
Total internal reflection needs higher-to-lower index as well as a beyond-critical angle.
Question 4
At the critical angle, is the transmitted ray normal to the surface, along it, or absent in the limiting ray diagram?
Worked answer and reason
Along the surface, at 90° to the normal. Beyond the critical angle the transmitted ray is absent.
The critical condition follows by setting the transmitted-angle sine equal to one.
JavaScript enables saved drafts and self-assessment. You can always work on paper.
Catch the tempting mistake
- Light changes frequency when it enters glass.
- A stationary boundary keeps the source frequency fixed; speed and wavelength change.
- Any sufficiently steep incidence can cause total internal reflection.
- The ray must first be going from higher index to lower index.
- An inverse-sine input above one means round the angle to 90°.
- It means no real transmitted ray exists under the stated conditions.
Put it to work
Give the physical reason as well as the calculation. The worked solutions are on a separate page.
- Problem 5 · verbal and mathematical
- Problem 6 · derivation and boundary-case ray diagrams
- Problem 9 · experimental design and graph
- Problem 11 · data graph, experimental design, and prediction
Scientific calculator workspace
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Scientific calculator
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For the teacher
- Have learners identify medium 1 from the incoming arrow, rather than from table order.
- Use a semicircular block so the incoming ray can enter normally at its curved surface; this isolates refraction at the flat face.
- Check the two TIR conditions in words before calculating a critical angle.
Source objectives and scope
- 13.3.A — Describe the refraction of light between two media.
Suggested skills are teaching guidance. The course applies all science practices across its objectives.
Science references for this teaching
- College Board AP Physics 2 CED, Unit 13 (supplied pinned source) — Official Unit 13 requirements, plane/spherical mirror scope, and magnitude form of magnification
- OpenStax College Physics 2e: The Ray Aspect of Light — Ray and wavefront geometry; geometric-optics approximation
- OpenStax College Physics 2e: The Law of Reflection — Normal-angle law and local diffuse/specular reflection
- OpenStax College Physics 2e: Image Formation by Mirrors — Paraxial spherical mirrors, mirror distances, magnification
- OpenStax College Physics 2e: The Law of Refraction — Refractive index, speed, and Snell angles
- OpenStax College Physics 2e: Total Internal Reflection — Index-order condition and critical-angle boundary
- OpenStax College Physics 2e: Image Formation by Lenses — Thin-lens images, sign convention, and principal rays
Glossary and deeper reading · 6 refreshers
These editorial refreshers supplement the reading. Definitions and examples are added guidance; original source wording and recorded answers remain in their original context.
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Frequency
Frequency is the number of complete repeating cycles per unit time. It is measured in hertz, meaning cycles per second, and is the reciprocal of the period. For example, a vibrating string with a higher frequency produces more cycles each second.
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Refractive index
Refractive index is the ratio of light’s speed in vacuum to its speed in the material at the relevant frequency. It is dimensionless and can depend on wavelength. For example, glass usually has a larger refractive index than air, so visible light travels more slowly through the glass.
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Wave
A wave is a propagating disturbance that can transfer energy without transporting the medium as a whole. Mechanical waves require a material medium, while electromagnetic waves can propagate through vacuum. For example, a pulse travels along a rope while individual rope segments move locally around their equilibrium positions.
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Wavelength
Wavelength is the spatial distance between neighboring points at the same phase of a periodic wave. It connects propagation speed and frequency through speed equal to frequency times wavelength. For example, neighboring crests of a sinusoidal water wave are separated by one wavelength.
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Reflection
Reflection occurs when a wave returns from a boundary into the region from which it arrived. For a light ray at a surface, the reflection angle equals the incidence angle when both are measured from the local normal. For example, a smooth mirror produces an orderly image while a rough surface scatters reflected rays in many directions.
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Critical angle
The critical angle is the incidence angle at which the refracted ray would travel along the boundary toward a lower-index medium. At larger incidence angles the ideal model gives total internal reflection. For example, a ray leaving water for air can refract below the critical angle but undergo total internal reflection above it.