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2.5 Joint Probability and Disjoint Events — Answers and Rubrics

These solutions explain the new practice tasks in this lesson. For simulation parts, a valid recorded run may differ from another learner’s run; the rubric checks the model, recorded work and interpretation.

Original generated practice for the Fall 2026 course. Return to the lesson and independent checks.

Which Locker-Code Events Are Disjoint?: worked answer

A locker-code generator selects one integer uniformly from 1 through 10. Let A={1,2,3}, B={8,9,10}, C={2,4,6,8,10}, and D={8,9,10}. A trial is one selected code; every code has positive probability 1/10.

Part a

Calculate P(A intersect B), also writing the probability with the intersection symbol. Justify whether A and B are mutually exclusive using both possible joint outcomes and joint probability.

A∩B=∅A\cap B=\varnothing, so P(A intersect B)=P(A∩B)=0/10=0P(A\text{ intersect }B)=P(A\cap B)=0/10=0. No selected code can be in both sets; the events are mutually exclusive (disjoint).

Part a scoring criteria
Evidence for creditPoints
Shows no shared code and joint probability 0.1
Uses both probability notations and explicitly justifies mutual exclusivity.1

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Part b

Calculate P(C intersect D). Explain why this is a joint probability and justify whether C and D are disjoint. Distinguish the intersection set from its numerical probability.

C∩D={8,10}C\cap D=\{8,10\}; P(C∩D)=2/10=0.20P(C\cap D)=2/10=0.20. The probability concerns a code satisfying both conditions. Because 8 and 10 can satisfy both, C and D are not disjoint. The set {8,10} lists outcomes; 0.20 is its probability.

Part b scoring criteria
Evidence for creditPoints
Identifies {8,10} and probability .20.1
Explains both-event occurrence and non-disjointness.1
Distinguishes outcomes/set from probability number.1

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