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Inverse trigonometric integrals

This original textbook reading covers part of the AP topic. Follow the AP course outline for complete topic instruction and practice.

Inverse trigonometric integrals

$\int \frac{1}{\sqrt{1 - x^{2}}} d x = \sin^{- 1} x + C$ $\int - \frac{1}{x \sqrt{1 + x^{2}}} d x = \csc^{- 1} x + C$

$\int - \frac{1}{\sqrt{1 - x^{2}}} d x = \cos^{- 1} x + C$ $\int \frac{1}{x \sqrt{1 + x^{2}}} d x = \sec^{- 1} x + C$

$\int \frac{1}{1 + x^{2}} d x = \tan^{- 1} x + C$ $\int - \frac{1}{1 + x^{2}} d x = \cot^{- 1} x + C$

Index

Chapter 8 - Inverses Revisited

Chapter 8 - FFR - Substitution and Differentials

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