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Omniguides
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Answer Key

This original textbook reading covers part of the AP topic. Follow the AP course outline for complete topic instruction and practice.

This reading includes verified answer corrections and explicitly stated clarifications.

Chapter 1

  1. 1
  2. 23
  3. 4
  4. y=3sin[12(x-π)]+1
  5. Three possible answers:​
    ​
    y=3cos[12(x-2π)]+1​
    y=3cos[12(x+2π)]+1​
    y=-3cos(12x)+1
  6. g(x)=(1/2)ex-1+1
  7. Domain [−1,1]; range [−π/2,π/2].
  8. y=ln(201/ln4·161/ln10)≈3.3651
  9. 2+ln9-2lnπ
  10. Green e-x; blue -ex; orange -e-x; pink -ln(-x); cyan ln(-x); purple -lnx; yellow lnx.

Chapter 2

  1. ε=4δ
  2. 45
  3. 2
  4. 0
  5. 0
  6. No two-sided limit; right limit +∞, left limit -∞.
  7. -1/2
  8. 32
  9. 0
  10. Prove it

Chapter 3

  1. -2
  2. f′(x)=4x+4-2x-3
  3. 3ex-4x-2+(1/2)x-1/2, for x>0.
  4. sec2x-sinx, where cos x≠0.
  5. For sin x>0: -csc2x-cscxcotx. For sin x<0: csc2x-cscxcotx.
  6. x1=-1​
    x2=-23​
    x3=-133225
  7. Undefined, bad initial guess
  8. 12x+8+2x-3, for x≠0.
  9. f′′(x)=-sinx+cosx
  10. 3ex+48/x for x>0.

Chapter 4

  1. y′=ex(1+x)/(1-xex)2 where 1-xex≠0.
  2. [(x2-4)sec2x-2xtanx]/(x2-4)2.
  3. [(ex-4)sinx-2(ex-4x)cosx]/sin3x.
  4. 3/5
  5. y′=(y+3ex)/(3y2-x), where the original y≠0 and the displayed denominator is nonzero.
  6. y′=(siny-3x2y-8xsin(2x2))/(x3-xcosy).
  7. dydx=2x⋅siny⋅ecosx-x2⋅siny⋅ecosx⋅sinx1-x2⋅cosy⋅ecosx
  8. y′(π/4)=2/2-2.
  9. dydx=ex⋅cos(4x2+1)⋅siny-8x⋅ex⋅sin(4x2+1)⋅siny-y-2xx-ex⋅cos(4x2+1)⋅cosy
  10. dydx=y(cos2x⋅sin(ln(y))+y⋅cosx+x⋅y⋅sinx)cosx(y⋅cosx-x⋅cosx⋅cos(ln(y))-x⋅y)

Chapter 5

  1. 100e4≈5460 dollars/year under continuous compounding.
  2. 0 from the right.
  3. 0
  4. 0
  5. 2/(xln4)+3xlog2xln3·(log2x+1/ln2)+4/x, x>0.
  6. f′(x)=1x⋅ln2⋅(1+(log2x)2)-3(1-cos-1(x)2)⋅(1-x2)
  7. 1
  8. 5ln4/42x-1+2/[xx2-1(1+(arccscx)2)]+8xlnxln8·2lnx·xlnx-1, for x>1.
  9. f′(0)=2+ln3
  10. No real tangent slope at x=0.5.

Chapter 6

  1. Conditional on A(t)=10000et(e-t+0.07), A′(3)≈-423.62 dollars/year.
  2. 1000000e-1.5≈223130.16 dollars under the source’s continuous model.
  3. P=e5/3≈5.2945 dollars; sales 30000 units.
  4. Q=10000000/3≈1825.74 laptops in the continuous model; maximum profit ≈1217161.24 dollars; integer optimum 1826 laptops.
  5. Answers will vary
  6. 25
  7. a. 36​
    b. 4.75
  8. 3 cm²/s.
  9. dVdt=48cm3s
  10. -3/255/16≈-0.75147 rad/s, assuming the rigid ladder geometry in the source image.

Chapter 7

  1. 1
  2. 5.15
  3. 4π
  4. 32
  5. 0.3
  6. 3.2395055… square units.
  7. 7932=2.46875 square units.
  8. 75/64=1.171875 square units.
  9. 1
  10. The unit-width right sum is about 1.6449; it does not represent a finite exact area from zero.

Chapter 8

  1. 13
  2. -1x-32x-2+C
  3. -1/(3x)-1/(2x2)-1/(3x3)+C, x≠0.
  4. 6
  5. -π/4
  6. (1/3)ln(3x-2+(3x-2)2+1)+C
  7. The printed integral is not defined as a real integral over [0,6].
  8. arctan(x2-4)+C
  9. ln(x2+3/2+x4+3x2+2)+C.
  10. (1/2)ln|(x-1)/(x+1)|+C on 0<x<1 or x>1.

Chapter 9

  1. -ln|cscx+cotx|+C
  2. 0
  3. 512/5-32(4-2)3/2+(24/5)(4-2)5/2≈20.951317.
  4. 3sin-1(x3)+32sin(2sin-1(x3))+C
  5. ln|x|-2x2+C, x≠0.
  6. π/4, treating x=2 as a removable hole.
  7. π
  8. ln(cos(ln(cosx))+3)+C, on cos x>0.
  9. -ln|ln(cos(lnx))+3|+C where x>0, cos(ln x)>0, and ln(cos(ln x))+3≠0.
  10. x+23(1-x2)32+C

Chapter 10

  1. V=4πab2/3, for a>0 and b>0.
  2. 0.5854lunits3
  3. V(r)=4πr3/3, for r≥0.
  4. 0.333
  5. V=93π5≈58.4336 cubic units.
  6. For the clarified cavity below y=0, V=4α(6+α2)≈76.2594 mm³, where α=(3+21)/2.
  7. V=π[1−e−22−15]≈0.729894 cubic units.
  8. Prove it is V=13πr2h
  9. V=33π2/16+3π/2≈25.0684 cubic units.
  10. 5.5π2​

 

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