Introduction to Oxidation-Reduction
Supporting original reading. Follow the AP topic pathway for reviewed scope, worked reasoning and targeted practice.
Chemistry I · original Chapter 7 · combined Chapter 7
- What is Oxidation-Reduction?
- Oxidation States
- Characteristics of Oxidation-Reduction Reactions
- LEO-GER
Section 1
Introduction to Oxidation-Reduction
As described in the opening segment to this chapter, electrochemistry plays a very big role in many real world processes. It accounts for the way a your cell phone works, or your calculator, even your car. Electrochemistry can be very complex to understand because there are so many reactions that lie in the background of it and to understand it, we will need to learn a little bit of the background of electrochemistry which involves a type of chemical reaction know as oxidation-reduction reactions. Remember that when atoms interact with one another, there is a transfer of electrons that occurs as well as shared. Now looking at the bigger picture, when molecules interact with one another and reactions occur, there is a transfer of electrons. These reactions where there are one or more electrons transferred are known as oxidation-reduction reactions.
You can see this reaction occur when you mix solid sodium and chlorine gas. Solid sodium contains neutral sodium atoms and chlorine gas is made up of diatomic neutral compound as well.

The reaction above shows that two neutral compounds, when combined together will create a solid material which contains Na+ and Cl - ions. Notice here that those atoms could not have gotten those charges, if it was not for the transferring of electrons that occurred in the reaction.

None of the products formed are ionic in nature but for the products to be formed, there had to be transfer of some electrons from the carbon atom to the oxygen atom. To explain this, we need to go over oxidation states.
Oxidation States
Rules for Oxidation States
- The oxidation state for an atom in its elemental form is 0. For example, the oxidation states for Na(s), O2(g), Cl2(g) are all 0.
- Hydrogen has an oxidation state of +1 when it is in a covalent bond with nonmetals. For example, the oxidation states for hydrogen in HCl, H2O, HF,and H2S is +1.
- In binary compounds, the element with a greater affinity for electrons has a negative oxidation state equal to its charge in it’s ionic state. For example, in NH3, nitrogen has a charge of -3. In HF, fluorine has a charge of -1.
- Oxygen usually has oxidation number −2 in familiar compounds such as CO₂, H₂O and SO₃. In a peroxide, O₂²⁻, each oxygen has oxidation number −1. These are not the only exceptions: superoxide has average oxygen oxidation number −½, and oxygen bonded to fluorine can have a positive oxidation number. Oxidation number is electron-accounting bookkeeping; it is not always an atom’s actual charge.
- The sum of oxidation numbers is zero for a neutral species and equals the overall charge for a polyatomic ion. In H₂O, oxygen is −2 and each hydrogen is +1, so 2(+1)+(−2)=0. In NH₄⁺, each hydrogen is +1 and nitrogen is −3, giving (−3)+4(+1)=+1. Distinguish the sum for the species from the oxidation number assigned to an individual atom.
states for both the nitrogen and hydrogen atom is +1 meaning that if hydrogen has a +1 oxidation state for each atom, then nitrogen must only have a -3 oxidation state to give a overall state of +1.
What is important to note is that the charge and oxidation states are not the same thing! Oxidation states are just placeholders to help us keep track of the amount of electrons.
Now that you know the basic rules for assigning oxidation states, lets look at some examples.
Example 7.1.1
Let’s assign some oxidation states for the following compounds
i). SO2
ii.) PCl5
Alright, let’s use the rules that we just learned and apply them to these compounds.
i). The rule that is the most important here is the one about oxygen oxidation states. Remember that means that the oxidation state for oxygen is -2. In the case of this compound, there are two oxygen atoms and it is not a peroxide compound so the oxygen atoms have an overall
oxidation state of -4. Since the SO2 compound is a neutral compound, then we must use rule number 5. That means that the sum of the oxidation states for all the atoms must be zero. So since oxygen has a -4 oxidation state, that must mean that the sulfur atom has an oxidation state of +4, therefore giving an overall sum of zero.
ii.) The rule to apply here is rule three. Chlorine has a greater affinity for electrons therefore its oxidation state will be equal to it’s negative charge in its ionic state, so in this case each chlorine atom will have an oxidation state of -1; meaning that the sum of chlorine oxidation states is -5. Since PCl5 is neutral as well, P must have a +5 oxidation state to achieve a sum of zero.
iii.) The thing that’s different here is the overall charge of the compound is 2- meaning that the compound is not neutral so there is an imbalance in the oxidation states. We know that oxygen must remain at -2 oxidation states so since there are three of them that means the sum of the states is -6. In order to meet the 2- charge of the compound, the carbon atom must have an oxidation state that meets those requirements. In this case, it is +4, as it allows for two electrons to remain thus giving us the overall charge that we’re looking for.
Let’s recap these solutions in a more visual form where you can actually see the compounds. View the gallery on the next page.

If we are going to assign oxidation states to everything, the methane is neutral in charge so hydrogen would have a +1 for each atom totaling +4, meaning then that carbon has a -4 oxidation state. O2 is elemental oxygen in its diatomic state so it has an oxidation state of zero. CO2 is neutral as well, meaning that since O2 has an oxidation state of -4 (-2 for each O atom), carbon must have one of +4. H2O is the same way, its neutral so each hydrogen atom has a oxidation state of +1, while oxygen has it at -2.
In this reaction, there are no ionic compounds but everything can still be characterized with the flow and transfer of electrons. Notice here how the carbon changes from a -4 to a +4 oxidation state when being converted from CH4 to CO2. This means that there were 8 electrons that were transferred over.
Image 1
Oxygen goes from oxidation number 0 in O₂ to −2 per oxygen atom in the combustion products. For methane combustion, CH₄+2O₂→CO₂+2H₂O, four oxygen atoms each gain two electrons in the bookkeeping, for eight electrons total. The total electron transfer is eight; no individual oxygen has oxidation number −8.
Image 2
Important to note here that hydrogen doesn’t change oxidation states so it is not involved in the transfer of electrons.
Since we have a better understanding of this now, it is important to learn some new terms. Oxidation refers to an increase in oxidation state, so when an atom has in increase in oxidation state (losing electrons), it is normally said to be oxidized. Reduction is attributed to a decrease in oxidation state (gaining electrons) so atoms are therefore reduced.
Now we’re going to let you in here in a little secret on how to remember that little trick. Actually, its not really a trick because we’re sure you learned it one way or another. If this is new to you, then pay attention, cuz it’ll help!
You read that right, a lion named LEO, goes GER, not grrrrrr, but GER. Well the sound and actual action of a lion saying “grrr” is correct, but for acronym purposes, GER is better for us.
So what does it mean? Well here is a nice breakdown:
Image 3
So when electrons are lost, the unit is oxidized. When electrons are gained, they are reduced. So, every time you forget which is which, just remember LEO the lion goes GER.
Glossary and deeper reading · 7 refreshers
These editorial refreshers supplement the reading. Definitions and examples are added guidance; original source wording and recorded answers remain in their original context.
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Redox reaction
A redox reaction combines oxidation of one species with reduction of another. Electron loss and gain must balance in the net equation along with atoms and total charge. For example, zinc reducing copper ions involves zinc oxidation and copper-ion reduction.
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Oxidation number
An oxidation number is a formal electron-accounting value assigned using specified rules. Changes in oxidation number help identify oxidation and reduction but are not always actual atomic charges. For example, oxygen usually has oxidation number −2 in water while hydrogen has +1.
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Ion
An ion is an atom or group of atoms with a net electric charge. Ordinary ion formation changes electron count without changing the element's proton count. For example, a sodium atom losing one electron becomes a sodium ion with charge +1.
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Ionic bonding
Ionic bonding is electrostatic attraction among oppositely charged ions. An ionic solid normally forms an extended lattice rather than separate ion-pair molecules. For example, sodium chloride consists of a repeating array of sodium and chloride ions.
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Oxidation
Oxidation is electron loss, represented by an increase in oxidation number. It occurs together with reduction so that electrons are conserved in the overall reaction. For example, a zinc atom becoming a zinc ion with charge +2 undergoes oxidation.
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Reduction
Reduction is electron gain, represented by a decrease in oxidation number. It is paired with oxidation in an electron-transfer reaction. For example, a copper ion with charge +2 gaining two electrons to form copper metal undergoes reduction.
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Covalent bond
A covalent bond involves shared electron density between atoms. The sharing can be approximately equal or unequal depending on the atoms and their environment. For example, the bond in a hydrogen molecule shares electrons between two identical atoms.
